InterviewSolution
Saved Bookmarks
| 1. |
`lim_(xrarr0) (sinax)/(sinbx),a,bne0` |
|
Answer» `underset(xrarr0)"lim"(sinax)/(sinbx)(a,bne0) ((0)/(0))` `=underset(xrarr0)"lim"(sinax)/(ax).(bx)/(sinbx).(a)/(b)` `=1xx1xx(a)/(b)(because underset(0rarr0)"lim"(sintheta)/(theta)=1)` `=(a)/(b)` |
|