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`lim_(xrarr0)(|sinx|)/(x)` is equal toA. 1B. `-1`C. Does not existD. None of these |
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Answer» Correct Answer - c Given, limit = `lim_(xto0)(|sinx|)/(x)` `therefore` LHL=`lim_(xto0^(-))(-sinx)/(x) = -lim_(xto0)(sinx)/x=-1` RHL `=lim_(xto0^(+))(sinx)/(x) =1` `therefore` LHL `ne` RHL So, limit does not exist. |
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