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`lim_(xrarr0)(tan2x-x)/(3x-sinx)` is equal toA. 2B. `1/2`C. `-1/2`D. `1/4` |
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Answer» Correct Answer - b Given, `lim_(xto0)(tan2x-x)/(3x-sinx) = lim_(xto0)(x[(tan2x)/x-1])/(x[(3-(sinx)/x)])` `=(lim_(xto0)2xx(tan2x)/(2x)-1)/(3-lim_(xto0)(sinx)/(x))=(2-1)/(3-1)=1/2` |
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