` lim_(z to 1) (2^(1//3)-1)/(z^(1//6)-1)` – InterviewSolution

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1.	` lim_(z to 1) (2^(1//3)-1)/(z^(1//6)-1)`
Answer» `underset(zrarr1)"lim"(z^(1//3)-1)/(z^(1//6)-1) ((0)/(0))` `=underset(Zrarr1)"lim"((z^(1//6)^(2)-(1)^(2)))/(z^(1//6)-1)` `=underset(zrarr1)"lim"((z^(1//6)-1)(z^(1//6)+1))/(z^(1//6)-1)` `=underset(xrarr1)"lim"(z^(1//6)+1)=1+1= 2`.

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