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Liquid ammonia is used in ice factory for making ice from water. If water at `20^(@)C` is to be converted into 2 kg ice at `0^(@)C`, how many grams of ammonia is to be evaporated? (Given: The latent heat of vaporization of ammonia= 341 cal/g) |
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Answer» (1) Water Water `(20^(@)C)overset(mcDeltaT)to"Water" (0^(@)C) overset(mL)to"Ice"(0^(@)C)` `Q_(A) = mCDeltaT + mL…………..(i)` (2) Ammonia `Q_(B) = m_(1),L_(1)………..(ii)` from (i) and (ii) `Q_(A) = Q_(B)` `mcDeltaT + mL = m_(1)L_(1)` `2xx 1 xx(20 - 0) + (2xx 80) = m_(1) xx 341` ` 40 +160 = m_(1) xx 341` `200 = m_(1) xx 341` `m_(1) = (200)/(341)` ` m_(1) = 0.5865 kg` or `m_(1) = 586.5 g` Hence, 586.5g of ammonia has to be evaporated . |
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