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log\(\frac{a^2}{bc}\) + log\(\frac{b^2}{ac}\) + log\(\frac{c^2}{ab}\) equals(a) –1 (b) abc (c) 3 (d) 0 |
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Answer» (d) 0 log\(\frac{a^2}{bc}\) + log\(\frac{b^2}{ac}\) + log\(\frac{c^2}{ab}\) = log\(\bigg(\)\(\frac{a^2}{bc}\) x \(\frac{b^2}{ac}\) x \(\frac{c^2}{ab}\) \(\bigg)\) = log \(\bigg(\frac{a^2b^2c^2}{a^2b^2c^2}\bigg)\) log 1 = 0. |
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