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`loga/(y-z)=logb/(z-x)=logc/(x-y)` then value of `abc=`A. `a^(x)b^(y)c^(z)`B. `a^(y+z)b^(z+x)c^(x+y)`C. 1D. All of these |
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Answer» Correct Answer - D (i) Equate the given ratios to k and get the values of loga, logb and logc. (ii) Add log a, log b and log c and solve for abc. |
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