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Lowering of vapour pressure due to a solute in `1` molal aqueous solution at `100^(@)C` is a.`13.44 mm Hg` ,b. `14.14 mm Hg` ,c.`13.2 mm Hg` ,d. `35.2 mm Hg`A. `13.44`mmHgB. `14.12`mmHgC. `31.2`mmHgD. `35.2`mmHg |
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Answer» Correct Answer - A `m=(x_(B)xx1000)/(1-x_(B)m_(A))x_(B)` =mole fraction of solute `1=(x_(B)xx1000)/((1-x_(B))xx18)m_(A)` =mole mass of solvent `x_(B)=0.0176` `x_(A)=1-0.0176=0.9824` `p=p^(@)x_(A)` `760xx0.9824=746.62` `Deltap=P^(@)-p=760-746.62=13.4` |
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