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                                    Magnetic induction produced at the centre of a circular loop carrying current is B . The magnetic moment of the loop of radius R is (Me = permeability of tree space)A. `(BR^(3))/(2pi mu_(0))`B. `(2 pi BR^(3))/(mu_(0))`C. `(BR^(2))/(2 pi mu_(0))`D. `(2pi BR^(2))/(mu_(0))` | 
                            
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Answer» Correct Answer - B Magnetic moment `M = I xx A " " … (i)` Current `xx` Area of enclosed by loop Magnetic induction at the centre of circular loop `B = (mu_(0)I)/(2R) implies I = (2 BR)/(mu_(0))` Here , `A = pi R^(2) " " … (iii)` Substituting Eq.(ii)( and Eq.(iii) in Eq.(i) , we get `M = (2BR)/(mu_(0)) xx pi R^(2) = (2pi BR^(3))/(mu_0)`  | 
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