InterviewSolution
Saved Bookmarks
| 1. |
Magnitude of K.E. in an orbit is equal toA. Half of the potential energyB. Twice of the potential energyC. One fourth of the potential energyD. None of these |
|
Answer» Correct Answer - A K.E. of `e^-=1/2` of P.E. But K.E. is always positive . or `KE=-[1/2P.E.]=`-[Total Energy of system] |
|