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Mass number and atomic number of an atom are 232 and 90 respectively. How many `alpha-` particles of this atom must emit, after the emission of `2 beta-`particles, such that the mass number and atomic number of new element are 212 and 82 respectively |
Answer» Correct Answer - 5 `._(9)^(232)A overset(-2 beta)rarr ._(90)^(232)B rarr ._(82)^(212)C + m_(2)^(4) He` In above nuclear reaction, `232 = 212 + m xx 4` or `m = (232 - 212)/(4) = 5 alpha`- particles |
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