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Masses of two bodies are 1kg and 4kg respectively. If their kinetic energies are in 2:1 proportion, ratio of their speeds is ……………

Answer»

`2sqrt(2):1`
`1:SQRT(2)`
`1:2`
`2:1`

Solution :`m_(1)=1KG,m_(2)=4kg,(K_(1))/(K_(2))=2:1`
Now, `(K_(1))/(K_(2))=((1)/(2)m_(1)v_(1)^(2))/((1)/(2)m_(2)v_(2)^(2))=((1kg)v_(1)^(2))/((4kg)v_(2)^(2))`
`THEREFORE (2)/(1)=(1)/(4)(v_(1)^(2))/(v_(2)^(2)) therefore (v_(1)^(2))/(v_(2)^(2))=(8)/(1) therefore (v_(1))/(v_(2))=(2sqrt(2))/(1)`


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