InterviewSolution
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InterviewSolution
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Match the conditions/expressions in Column I with values in Column II `(sin 3 alpha)//cos2 alpha)` is `{:(" Column I"," Column II"),("A. Positive","p."(13pi//48, 14pi//48)),("B. negative","q."(14pi//48, 18pi//48)),(,"r."(18pi//48, 23pi//48)),(,"s."(0, pi//2)):}` |
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Answer» Correct Answer - A `rarr` r; B `rarr` p In the interval `((13pi)/(48),(14pi)/(48)),cos2 alpha lt 0 and sin 3 alpha gt 0`. `implies(sin3alpha)/(cos2alpha)` is negative, therefore B `rarr` p. Again in the interval `((18pi)/(48),(23pi)/(48))`, both `sin 2 alpha` and `cos 2 alpha` are negative, so `(sin 3 alpha)/(cos 2 alpha)` is positive, therefore A`rarr r. |
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