1.

Maximum profit: A barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000where P(x) is the profitin rupeesand x is the numberof barrelsmade and sold. Based on this model answer the following questions: When no barrels are produce what is a profit loss?

Answer»

22000
66000
11000
33000

Solution :When no BARRELS are produced, X = 0
`P(x) = 0+0 -6000 `
`P(x) = -66000`
Thus (B) is CORRECT option.


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