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Maximum profit: A barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000where P(x) is the profitin rupeesand x is the numberof barrelsmade and sold. Based on this model answer the following questions: When no barrels are produce what is a profit loss? |
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Answer» 22000 `P(x) = 0+0 -6000 ` `P(x) = -66000` Thus (B) is CORRECT option. |
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