1.

Maximum profit: An barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000where P(x) is the profitin rupeesand x is the numberof barrelsmade and sold. Based on this model answer the following questions: What is the break even point ? (Zero profit point is called break even)

Answer»

10 barrels
30 barrels
20 barrels
100 barrels

Solution :At break-even point `P(x) = 0`, thus
`0 = -10x^(2) +3500x -66000`
`x^(2) +350x +6600=0`
`x^(2)-330x-20x+6600=0`
`x(x-330) -20(x+300)=0`
`(x-330) (x-20)=0`
`x=20, 330`
Thus, (c ) is correct option.


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