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InterviewSolution
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Maximum profit: An barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000where P(x) is the profitin rupeesand x is the numberof barrelsmade and sold. Based on this model answer the following questions: What is the maximum profit which can manufacturer earn? |
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Answer» <P>Rs 240250 `P(X) = -10X^(2) +3500x - 66000` `= -10 (x^(2) -350x +6600)` `= -10 [(x-175)^(2) -30625 +6600]` `=-10 [(x-175)^(2) -24025]` `= -10(x-175)^(2)+240250` From above equation it is clear that maximum value of P(x) is 240250. THUS (a) is correct option. |
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