1.

Maximum profit: An barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000where P(x) is the profitin rupeesand x is the numberof barrelsmade and sold. Based on this model answer the following questions: What is the profit/loss if 400 barrels are produced

Answer»

<P>Profit 266200
Loss 266200
Profit 342000
Loss 342000

Solution :`P(400)= - 10(400)^(2) +3500 (400) - 66000= -266000`
Thus (B) is correct OPTION.


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