Metal M forms two oxides A and B in which the ratioof the number of ozygen atoms to the totalnumber of atoms present in themolecule is3 : 5 and 1 : 2, respectively. Determine theformiulae of A andB.

Metal M forms two oxides A and B in which the ratioof the number of oz

1.	Metal M forms two oxides A and B in which the ratioof the number of ozygen atoms to the totalnumber of atoms present in themolecule is3 : 5 and 1 : 2, respectively. Determine theformiulae of A andB.
Answer» SOLUTION :Metal ions PRESENT in A and B are `M^(+a) and M^(+b)`, RESPECTIVELY . ` :." Formula of A is " M^(+a)O^(-2) rArr M_(2)O_(a)` ` :. " Ratio " = a/(2+a) = 3/5` ` rArr 5a = 6 + 3a rArr2a = 6 rArr a = 3` ` :. " Metal oxide A is " M^(+3)O^(-2) rArr M_(2)O_(3)` Formula of B is ` M^(+b),O^(-2) rArr M_(2)O_(b)` ` :." Ratio " = b/(2+b) = 1/2` ` rArr2b = 2 + b rArr b = 2` `:." Metal oxide B is" M^(+2),O^(-2) rArr MO`