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Molarity of liquid HCl with density equal to `1.17 g//mL` is:A. `36.5`B. `18.25`C. `32.05`D. `42.10` |
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Answer» Correct Answer - 3 `Density=(mass)/(volume)=1.17 g//c c` This implies that in every `1 c c` there is `1.17 g HCl`. Thus, mass of `HCl` in `1000 c c (1000 mL or 1 L)` will be `1170 g`. `n_(HCl)=(mass_(HCl))/(mm_(HCl))` `=(1170 g)/(36.5 g mol^(-1))=32.05 mol` `M_(HCl)=n_(HCl)/V_(mL)xx(1000 mL)/L` `=(32.05 mol)/(1000 mL)xx(1000 mL)/L` `=32.05 M` |
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