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Mole fraction of a solution in 1.00 molal aqueous solution isA. `0.1770`B. `0.0177`C. `0.0344`D. `0.83` |
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Answer» Correct Answer - B For electrolytes, `Delta T_(f)=ixxk_(f)xxm` (min molarity) or `Delta T_(f)=ixxk_(f)xx(W_(2))/(M_(2))xx(1000)/(W_(1)), Delta T_(f)=3.82^(@)C` `k_(f)=1.86 K kg mol^(-1), M_(2)=142` for `Na_(2)SO_(4)` `W_(2)=5g, W_(1)=45.0g` `therefore 3.82=ixx1.86xx(5)/(142)xx(1000)/(45)` `therefore i=(3.82xx142xx45)/(1.86xx5xx1000)=2.63` |
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