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Mole fraction of ` C_(3)H_(5)(OH)_(3) `in a solution of ` 36 g ` of water and ` 46 g `of glycerine is :A. ` 0.46 `B. ` 0.36 `C. ` 0.20 `D. ` 0.40 ` |
Answer» Correct Answer - C Mole of ` H_(2)O = (36)/(18)=2` Mol e of glycerine =` (46)/(92) =0.5 ` total Mo le =` 2=0.5 =2.5 ` Mole fraction of glycerine = ` (n_(1))/(n_(1)+n_(2)) =(0.5)/(2.5)X_(0)=0.2 ` |
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