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Mole fration of a solute in 2.0 molal aqueous solutions is :A. 1.77B. 1.87C. 0.0347D. 0.347 |
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Answer» Correct Answer - c `"Mole fraction of solute"(X_(B))=n_(B)/(n_(B)+n_(A))` `"No, of moles of solute"(n_(B))=2 mol` `"No. of moels of water"(n_(A))=((1000g))/((18g mol^(-1)))` =55.55 mol `X_(B)=((2 mol))/((57.55 mol))=0.0347` |
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