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(Mole to Mole calculation) How many moles of NH_(3) can be produced from 2.0 mol H_(2) in the reaction N_(2)(g)+3H_(2)(g) to 2NH_(3)(g)?

Answer»

SOLUTION :From the balanced CHEMCIAL equation, we see that 3 mol `H_(2)` reacts (with 1 mol `N_(2)`)to give 2 mol `NH_(3)""THEREFORE` 2.0 mol of `H_(2)=(2)/(3)xx2=(4)/(3)=1.33" mol of "NH_(3)`.


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