Momentum of a body is doubled. By what percent does its KE change? – InterviewSolution

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1.	Momentum of a body is doubled. By what percent does its KE change?
Answer» Solution :K.E. `=(p^(2))/(2m)` when p is DOUBLED K.E. becomes 4 times. `:.` % Increase in K.E. `=(DeltaK.E.)/(K.E)XX100=(4K.E-K.E.)/(K.E.)xx100` `=3xx100=300%`

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