1.

N_(2)+3H_(2)rarr 2NH_(3) (The atomic mass of nitrogen is 14, and that of hydrogen is 1) "1 mole of nitrogen "(………….g)+ "3 moles of hydrogen "(……….g)rarr "2 moles of ammonia "(……….g)

Answer»

Solution :`N_(2)+3H_(2)rarr 2NH_(3)`
1 mole of `N_(2)=28g`
3 MOLES of `H_(2)=6g`
2 moles of `NH_(3)=34g`
1 mole of nitrogen `(28g)+3` moles of HYDROGEN `(6g)rarr2` moles of Ammonia (34g)


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