n resistors, each of resistances R are first connected in series so as to give an effective resistance R_s Subsequently these resistors are connected in parallel so as to give an effective resistance R_p. Then the ratio R_s/R_p will be

n resistors, each of resistances R are first connected in series so as

1.	n resistors, each of resistances R are first connected in series so as to give an effective resistance R_s Subsequently these resistors are connected in parallel so as to give an effective resistance R_p. Then the ratio R_s/R_p will be
Answer» `N:1` `n^2:1` `1:n^2` `1:n` SOLUTION :In series ARRANGEMENT `R_s=R+R+R`….n times =nR In parallel arrangement `1/R_p=1/R+1/R+1/R…. N time s=n/R or R_p=R/n` `THEREFORE R_s/R_p=(nR)/((R/n))=n^2`