`NaCl` is added to`1` litre water to such an extent that `DeltaT_(f)//K_(f)` becomes to `(1)/(500)`,wt.of `NaCl` added toA. `5.85g`B. `0.585g`C. `0.0585g`D. `0.0855g`

`NaCl` is added to`1` litre water to such an extent that `DeltaT_(f)//

1.	`NaCl` is added to`1` litre water to such an extent that `DeltaT_(f)//K_(f)` becomes to `(1)/(500)`,wt.of `NaCl` added toA. `5.85g`B. `0.585g`C. `0.0585g`D. `0.0855g`
Answer» Correct Answer - C For `NaCl i=2` or`DeltaT_(f)=i.K_(f).m` `DeltaT_(f)//K_(f)=2.m.` Or =`2m` Or molarity `=(1)/(1000)or(1)/(1000)` moles are dissolved `Kg^(-1)`of water or approximately `(1)/(1000)`moles are present in `1.0` litre of water(considering molarity and molality to be the same) `:.` Weight of `NaCl=(1)/(1000)xx58.5 g` of `NaCl` `= 0.0585 g` of NaCl.

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`NaCl` is added to`1` litre water to such an extent that `DeltaT_(f)//K_(f)` becomes to `(1)/(500)`,wt.of `NaCl` added toA. `5.85g`B. `0.585g`C. `0.0585g`D. `0.0855g`

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