1.

Name the gas evolved when ethanoic acid reacts with sodium carbonate. How would you identify this gas?

Answer»

Solution :The gas evolved is carbon DIOXIDE `(CO_(2))`. The reaction is as FOLLOWS:
`underset("Ethanoic ACID")(2CH_(3)COOH)+underset("carbonate")underset("Sodium")(Na_(2)CO_(3)) to underset("ethanoate")underset("Sodium")(2CH_(3)COONA)+underset("dioxide")underset("Carbon")(CO_(2))+underset("WATER")(H_(2)O)`
When this gas is passed through lime water, it turns milky. The milky colour of lime water confirms that the gas is carbon dioxide `(CO_(2))`.


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