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Naturally occureing boron consists of two insotopes whose atomic weight are `10.01 and 11.01 ` The atomic weight of the natural boron is `10.81 ` Calkculate the precentage of e ach isotopes in natURAL BORON |
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Answer» Let the percentage of the isotope be a percentage of the second isotope will be `100 - a ` `10.81 = ((a xx 10.01) + (100 - a) xx 11.01)/(100)` On solving we get `a = 20,(100 - a) = 80` |
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