1.

Nichrome wire of length l and radius r has resistance of 10 Omega . How would the resistance of the wire change when : (i) Only length of the wire is doubled ? (ii) Only diameter of the wire is doubled ? Justify your answer .

Answer»

Solution :(i) `R prop L`
So resistance BECOMES TWO times i.e R `=20 Omega`
(II) `R prop (1)/(A) prop (1)/(d^(2))`
So when diameter is doubled resistance becomes one fourth of the original i.e., R = 2.5 `Omega`


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