InterviewSolution
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InterviewSolution
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Nuclei of a radioactive element `X` are being produced at a constant rate `K` and this element decays to a stable nucleus `Y` with a decay constant `lambda` and half-life `T_(1//3)`. At the time `t=0`, there are `N_(0) `nuclei of the element X. The number `N_(Y)` of nuclei of `Y` at time `t` is .A. `qt-((q-lambdaN_(0))/(lambda))e^(-lambda t)+(q-lambdaN_(0))/(lambda)`B. `qt+((q-lambdaN_(0))/(lambda))e^(-lambda t)`C. `qt+((q-lambdaN_(0))/(lambda))e^(-lambda t)+(1-lambdaN)/(lambda)`D. `qt-((q-lambdaN_(0))/(lambda))e^(-lambda t)` |
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Answer» Correct Answer - C `(dN_(Y))/(dt)=lambdaN_(X)=lambda(1)/(lambda)[q-(q-lambdaN_(0))e^(-lambda t)]` `rArr N_(Y)=qt+((1-lambdaN_(0))/(lambda))e^(-lambda t)- (q-lambdaN_(0))/(lambda)` |
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