InterviewSolution
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InterviewSolution
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Nuclei of a radioactive element `X` are being produced at a constant rate `K` and this element decays to a stable nucleus `Y` with a decay constant `lambda` and half-life `T_(1//3)`. At the time `t=0`, there are `N_(0) `nuclei of the element X. The number `N_(Y)` of nuclei of `Y` at time `t` is .A. `Kt-(K-lambda N_(0))/(lambda)e^(-lambda t)+K-lambda(N_(0))/(lambda)`B. `Kt-(K-lambda N_(0))/(lambda)e^(-lambda t)+K-lambda(N_(0))/(lambda)`C. `Kt+(K-lambda N_(0))/(lambda)e^(-lambda t)`D. `Kt+(K-lambda N_(0))/(lambda)e^(-lambda t)` |
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Answer» Correct Answer - b `(dN_X)/(dt)=K-lambda N_(X)` N_(X)=(1)/(lambda)[K-K-lambda N_(0))e^(-lambda t)]` `(dN_(Y))/(dt)=lambdaN_(X)` `N_(Y)=Kt+(K-lambda N_0/lambda)e^(-lambda t) -(K-lambda N_(0))/(lambda)`. |
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