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Obtain an expression for equivalent resistance of two resistors connected in a series combination. |
Answer» Solution :Two resistors of resistance `R_(1)` and `R_(2)` are connected in series. LET I be the current flowing through the CIRCUIT The current through each resistor is ALSO I. The two resistors joined in series is replaced by an equivalent SINGLE resistor of resistance R such that the potential difference V across it, and the current I through the circuit remains same.![]() As `V=IR , V_(1)=IR =IR_(1),V_(2)=IR_(2)` `IR=IR_(1)+IR_(2)` `IR=I (R_(1)+R_(2)) or R= R_(1)+R_(2)` . |
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