Obtain the admittance of the last two elements in the parallel combination after transformation in the circuit shown below.(a) 1+s(b) 2+s(c) 3+s(d) 4+sThis question was posed to me during an internship interview.My doubt is from Series and Parallel Combination of Elements topic in section S-Domain Analysis of Network Theory

Obtain the admittance of the last two elements in the parallel combina

1.	Obtain the admittance of the last two elements in the parallel combination after transformation in the circuit shown below.(a) 1+s(b) 2+s(c) 3+s(d) 4+sThis question was posed to me during an internship interview.My doubt is from Series and Parallel Combination of Elements topic in section S-Domain Analysis of Network Theory
Answer» RIGHT choice is (d) 4+s To explain I would SAY: The term admittance is defined as the INVERSE of IMPEDANCE. The admittance of capacitor is 1/s and the admittance of resistor is 1/4 mho. So the admittance of the last two ELEMENTS in the parallel combination is Y1(s) = 4 + s.

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