Obtain the IUPAC name of the following compounds systematically. (i) CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH_(3) (ii) CH_(3)-overset(CH_(3))overset(|)(CH)-CH_(2)-CH_(2)-CH_(3)

Obtain the IUPAC name of the following compounds systematically. (i)

1.	Obtain the IUPAC name of the following compounds systematically. (i) CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH_(3) (ii) CH_(3)-overset(CH_(3))overset(\|)(CH)-CH_(2)-CH_(2)-CH_(3)
Answer» Solution :(i) `CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH_(3)` Step 1: It is a five- CARBON chain and hence the root word is .PENT.. (RULE 1) Step 2: All the bonds between carbon atoms are single bonds, and thus the suffix is .ane.. So, its name is Pent + ane = Pentane (II) `CH_(3)-overset(CH_(3))overset(\|)(CH)-CH_(2)-CH_(2)-CH_(3)` Step 1: The longest chain contains five carbon atoms and hence the root word is .Pent.. Step 2: There is a SUBSTITUENT. So, the carbon chain is numbered from the left end, which is closest to the substituent. (Rule 2) `underset(to)(overset(1)(C)H_(3)-overset(CH_(3))overset(\|2)(CH)-overset(3)(C)H_(2)-overset(4)(C)H_(2)-overset(5)(C)H_(3))` Step 3: All are single bonds between the carbon atoms and thus the suffix is .ane.. Step 4: The substituent is a methyl group and it is located at second carbon atom. So, its locant number is 2. Thus the prefix is .2-Methyl.. (Rule 6). The name of the compound is 2-Methyl + pent +ane = 2-Methylpentane