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Obtain the transform impedance of the network shown below.(a) (6s-8)/(4s^2+19s-4)(b) (6s+8)/(4s^2+19s+4)(c) (6s+8)/(4s^2-19s+4)(d) (6s-8)/(4s^2+19s+4)I have been asked this question during an interview.This key question is from Series and Parallel Combination of Elements topic in portion S-Domain Analysis of Network Theory |
Answer» RIGHT option is (B) (6s+8)/(4s^2+19s+4) Explanation: The term impedance is the inverse of the term admittance. We got admittance as Y2(s) = (4s^2+19s+4)/(6s+8). So the TRANSFORM impedance of the network is Z (s) = 1/Y2(s) = (6s+8)/(4s^2+19s+4). |
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