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InterviewSolution
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On a 60 km track, a train travels the first 30 km with a uniform speed of 30 kmh^(-1). How fast must the train travel the next 30 km so as to average 40 kmh^(-1) for the entire trip ? |
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Answer» Solution :`V_("AVG")=(S_(1)+S_(2))/(t_(1)+t_(2))=(S+S)/(S((1)/(V_(1))+(1)/(V_(2))))=(2V_(1)V_(2))/(V_(1)+V_(2))` or `40=(2xx30xx v_(2))/(V_(1)+V_(2)) rArr V_(2) =60 KMH^(-1)` |
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