On a graph paper draw a straight line represented by the equation 2x-3y+132=0. Use the graph drawn to find the values of m and n so that the points (m,-2) and (3,n) lie on the given straight line.

On a graph paper draw a straight line represented by the equation 2x-3

1.	On a graph paper draw a straight line represented by the equation 2x-3y+132=0. Use the graph drawn to find the values of m and n so that the points (m,-2) and (3,n) lie on the given straight line.
Answer» Solution :GIVEN equation is 2x-3y+12=0 `rArr` , 2x=3y-12 `rArr , x=(3y-12)/(2)` Let y = 0 `rArr x=(3xx0-12)/(2)=-6` Let y =2 `rArr x=(3xx2-12)/(2)=-3` Let y = 4 `rArr x=(3xx4-12)/(2)=0` Table for values : Point the points (-6,0), (-3, 2), (0, 4) on the same graph PAPER. Since point (m,-2) LIES on the straight line drawn through y = -2 draw a straight line which meets line AB at point A. draw a vertical line through A WHIHC meets x axis at point x= -9 `therefore` m=-9 Also (3,n) lies onthe straight line drawn through x= 3 .Draw a vertical line which meets the straight line at point B. Through point B draw a horizontal line which meets y axis at the point y =6