1.

Onanalysingan impuresampleof sodiumchloride, thepercentageof chloridewasfoundto be45.5whatis thepercentageofpuresodiumchloridein thesample?

Answer»

Solution :Molecular(orFormula )
MASSOF pureNaCl= Atomicmassof `Na+`
Atomicmassof CL
`=23+35.5=58.5 u`
Percentageof CHLORINEIN pureNaCl
`=(35.5 )/(58.5 )xx100 =60.6`
Now, ifChlorineis60.6 parts , NACL= 100 Parts
Ifchlorineis 45.5parts,NaCl `=(45.5 )/(60.6 ) xx 100 =75 `
Thus , PERCENTAGE of pure`NaCl =75 %`


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