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One energy difference between the states `n = 2` and `n= 3` is `EeV`, in hydrogen atom. The ionisation potential of `H` atom is -A. 3.2 EB. 5.6 EC. 7.2 ED. 13.2 E |
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Answer» Correct Answer - C ( c) Ionization energy `= E_prop - E_n` =`0 - [-(Z^2)/(n^2) xx 13.6 eV]` =`(Z^2)/(n^2) xx 13.6 eV` `13.6 Z_2 ((1)/(n_1^2) -(1)/(n_2^2))` `n_1 = 2, n_2 = 3` =`13.6 xx 1((9 - 4)/(4 xx 9))` =`(5)/(9) xx 13.6 = 7.2 E`. |
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