InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
One mole of a compound AB reacts with 1 mole of a compound CD according to the equation `AB + CD hArr AD + CB`. When equilibrium had been established it was found that `(3)/(4)` mole each of reactant AB and CD has been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction isA. `9//16`B. `1//9`C. `16//9`D. 9 |
|
Answer» Correct Answer - D `AB +CD hArr AD +CB` Original concentration of `[AB]=[CD]=(1)/(V)` mol `L^(-1)` where V is the volume of the vessel in L. `K_(c )=([AD][CB])/([AB][CD])` At equilibrium `[AB]=[CD]=(1-3//4)/(V)=(1)/(4V)"mol" L^(-1)` `[AD]=[CB] =(3)/(4V) "mol" L^(-1)` `K_(c )=(((3)/(4V))((3)/(4V)))/(((1)/(4V))((1)/(4V)))=9` |
|