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One mole of `N_(20O_(4)(g)` at 300K is kept in a closed container under one atmosphere. It is heated to 600K when 20% of `N_(2)O_(4)(g)` is converted to `NO_(2)(g)` `N_(2)O_(4)hArr 2NO_(2)(g)` Hence resultant pressure is `:`A. 1.2 atmB. 2.4 atmC. 2.0 atmD. 1.0 atm |
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Answer» Correct Answer - B `{:(,N_(2)O_(4),hArr,2NO_(2),),("Initial",1 mol,,,),("Equilibrium",0.8 mol,,0.4 mol,):}` Total moles at equilibrium `=0.8 +0.4 =1.2` mol Pressure due to 1 mol when temperature is doubled `(300-600K) ` is 2 atm. |
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