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Our designed Mach number is 0.8. Find the required area ratio for the design. Assume isentropic relation is valid.(a) 1.038(b) 3.45(c) 5.64(d) 0.12This question was addressed to me during an interview.My question comes from Propulsion topic in chapter Propulsion and Fuel System Integration of Aircraft Design

Answer»

The correct OPTION is (a) 1.038

For EXPLANATION: Given, Mach NUMBER M=0.8

Now, area ratio is given by, A/A* = (1/M)*(1+0.2M^2)^3*0.5787 = (1/0.8)*(1+0.2*0.8^2)^3*0.5787

A/A* = 0.7233*1.128^3 = 1.038.



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