InterviewSolution
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InterviewSolution
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`overset(-pi//4)underset(-pi//4)int e^(-x)sin x" dx"` isA. `-(1)/(2)e^((-pi)/(2))`B. `-(sqrt2)/(2)e^((-pi)/(4))`C. `-sqrt2(e^((-pi)/(4))+e^((-pi)/(4)))`D. 0 |
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Answer» Correct Answer - A `int_(-pi//4)^(pi//2)e^(-x)sin xdx=[(e^(-x))/(2)(-sin x -cos x)]_((-pi)/(4))^((pi)/(2))` `=(1)/(2)[e^(-x)(-sin x -cosx)]_(-pi//4)^(pi//2)` `=(1)/(2)[e^((-pi)/(2))(-1-0)-{e^((pi)/(2))((1)/(sqrt2)-(1)/(sqrt2))}]` `-(e^((-pi)/(2)))/(2)` |
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