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P And Q Can Complete A Work In 20 Days And 12 Days Respectively. P Alone Started The Work And Q Joined Him After 4 Days Till The Completion Of The Work. How Long Did The Work Last ? |
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Answer» Work DONE by P in 1 DAY = 1/20 Work done by Q in 1 day = 1/12 Work done by P in 4 days = 4 × (1/20) = 1/5 Remaining work = 1 – 1/5 = 4/5 Work done by P and Q in 1 day = 1/20 + 1/12 = 8/60 = 2/15 Number of days P and Q take to COMPLETE the remaining work = (4/5) / (2/15) = 6 Total days = 4 + 6 = 10 Work done by P in 1 day = 1/20 Work done by Q in 1 day = 1/12 Work done by P in 4 days = 4 × (1/20) = 1/5 Remaining work = 1 – 1/5 = 4/5 Work done by P and Q in 1 day = 1/20 + 1/12 = 8/60 = 2/15 Number of days P and Q take to complete the remaining work = (4/5) / (2/15) = 6 Total days = 4 + 6 = 10 |
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