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P Can Finish A Work In 18 Days. Q Can Finish The Same Work In 15 Days. Q Worked For 10 Days And Left The Job. How Many Days Does P Alone Need To Finish The Remaining Work ? |
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Answer» <P>Work DONE by P in 1 day = 1/18 Work done by Q in 1 day = 1/15 Work done by Q in 10 days = 10/15 = 2/3 Remaining work = 1 – 2/3 = 1/3 Number of days in which P can FINISH the remaining work = (1/3) / (1/18) = 6 Work done by P in 1 day = 1/18 Work done by Q in 1 day = 1/15 Work done by Q in 10 days = 10/15 = 2/3 Remaining work = 1 – 2/3 = 1/3 Number of days in which P can finish the remaining work = (1/3) / (1/18) = 6 |
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