1.

P–V plots for two gagesduring adiabatic process are shown in fig.Plots 1 & 2 should correspond respectively to

Answer»

`He and O_2`
`O_2 and He`
`He and Ar`
`O_2 and N_2`

SOLUTION :In an ADIABATIC PROCESS, SLOPE of P-V graph `=(dP)/(dv) =-gammaP/V`
i.e. slope `propgamma` (with - ve sign)
So `("slope")_2 gt ("slope")_1 :.gamma_2gt gamma_1`
`:.` PLOT 1 correspnds to `O_2 (gamma=1.4)` and Plot 2 corresponds to He `(gamma=1.67)`


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