InterviewSolution
Saved Bookmarks
| 1. |
Partial pressure of `N_(2)` gas at 298 K is 0.987 bargt If is bubbled through water at 298 K, how many millimoles of `N_(2)` gas would be dissolved in 1 litre of water ? (Given : `K_(H)` for `N_(2)` at 298 K =76.48 bar). |
|
Answer» `p=K_(H).x rArr x=(p)/(K_(H))` `rArr x=(0.987)/(76.48xx10^(13))=1.29xx10^(-5)` 1 litre of water =55.5 mole of water `rArrx=(n_(N_(2)))/(n_(N_(2))+55.5)~~(n_(N_(2)))/(55.5)=1.29xx10^(-5)` `rArr n_(N_(2))=7.16xx10^(-4)"mol"` =0.716 millimole |
|