1.

PendulumA isx cmshorterthan asecondspendulum and pendulum B is x cm longerthan the secondspendulum . Theratio oftheirtimeperiods is 3: 4 . Thelength of the pendulum with higherfrequency is

Answer»

86 cm
114 cm
128 cm
72 cm

Solution :Unitsof SurfaceTension `=N m^(-1)`
work`xx` volume `xx` speed `=(N m) xx (m^(3)) xx m s^(-1)`
`=N m^(5) s^(-1)`
`("work "xx" VELOCIT ")/("volume ")= ((N m ) xx (m s^(-1))/(m^(3)) =NM^(-1)s^(-1)`
`(" work" xx "velocity")/(" rateof change of volume") =((Nm)xx(ms^(-1)))/(m^(3)) =N m^(-1)s^(-1)`
`("work")/("time") xx (" volume")/("velocity") =(Nm)/(s^(-1)) xx (m^(3))/(ms^(-1)) =N m^(3) s^(2)`


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