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Percentage of a radioactive element decayed after 20 s when half-life is 4 sA. 92.25B. 96.87C. 50D. 75 |
Answer» Correct Answer - B `n = (20)/(4) = 5, (N_(t))/(N_(0)) = ((1)/(2))^(5) = (1)/(32), :.` decayed `= (1 -(1)/(32)) xx 100 = (31)/(32) xx 100 = 96.87` |
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